Project Euler Problem 6

The sum of the squares of the first ten natural numbers is, 12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

$i = 1;
$n = 0;
while ($i < 101) {
      $n += $i;
      $sum += pow($i, 2);
      $i++;  
}  
$number = pow($n, 2); 
echo $number - $sum;

This was extremely easy. What did you get?